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ma cross of RSI
Ok can anyone assist on this one please.
Looking for a default daily setting RSI 14 with a SMA 9 overlay to it, showing both a 9 SMA and 14 RSI cross at the 50 level.
As well the same as above with the 45 EMA cross of a default RSI 14 both over the 50 level. Have beat my head to death trying to figure out so any help is greatly appreciated . Also this would be EOD close settings. Thanks in advance.
Looking for a default daily setting RSI 14 with a SMA 9 overlay to it, showing both a 9 SMA and 14 RSI cross at the 50 level.
As well the same as above with the 45 EMA cross of a default RSI 14 both over the 50 level. Have beat my head to death trying to figure out so any help is greatly appreciated . Also this would be EOD close settings. Thanks in advance.
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Best Answers
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I assume as this is under the "SharpCharts" section you are just looking for how to plot this on a chart. See the following link, note the SMA9 overlay is under the advanced options.
http://stockcharts.com/h-sc/ui?s=GG&p=D&b=5&g=0&id=p36145666868
If you are looking for a way to scan for this type of indicator and overlay see the following article.
http://stockcharts.com/articles/scanning/2011/08/question-is-it-possible-to-use-an-ema-of-an-indicator-in-a-scan-for-example-if-i-wanted-to-know-when-rsi5-is-above-a.html0 -
No problem I relocated the question under the scanning section.
Have a look at the second article, it addresses this type of scan. I've modified the coding to be more specific to your case.
[type = stock] and [country = us]
and [ RSI(14) X 50 ]
and [ SMA(9,RSI(14)) X 50]
The scan does get a few hits, however it is fairly rare to get hits with a scan that requires two criteria to cross on the same day. Thus you might be missing quite a few good charts, I would try adjusting the crossover values, say use 50 & 45 instead of 50 & 50. Play around with the settings and review the charts.0
Answers
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Whoops my bad i know how to plot and i am sorry can this be relocated to the "scanning" forum? Sorry I am looking for how to scan for the condition. Thanks and sorry for putting this in the wrong place.0
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Thanks Gord for taking the time to answer my question. I have tried the article that you mentioned and modified as i to was getting not many hits. Once again thank you for you time.0
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