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EMA 8 and 21 crossover scan help needed
Comments
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The second parts are easy
and [close > 30]
and [sma(?, volume) > 500000] // you decide length of MA where ? is
Then you have to decide the direction of the crossover. MA 8 is faster, so it will always do the crossing, but there is no "cross below" operator, only "x", which is "cross above"
So for 8 crosses above 21
and [ema(8,close) x ema(21,close)]
but for 8 crosses below 21, you have to write it as if 21 crosses above 8, so:
and [ema(21,close) x ema(8, close)]0
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