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Crash scan
Best Answer
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I think it would be hard to write one scan that would capture all possible situations to fit that description, so you have to make some decisions.
Here's a scan that finds instances where the 5 year low occurred in the past year (52 weeks) and the 5 year high occurred at least a year ago:
// the current 1 year low is the same as the current 5 year low
and [weekly min(52, weekly low) = weekly min(260, weekly low)]
// the current 1 year high is below the 5 year high
and [weekly max(52, weekly high) < weekly max(260, weekly high)]
You can vary the parameters to find different configurations.
0
Answers
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Thank you very much0
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