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Scan using multiple math equations
Hi, I am having trouble creating a scan with multiple equations. I was hoping someone could help. Here is what I am trying to achieve.
1. I want the close to have crossed above the following combined level, therefore
[close x
2. The level I want the close to exceed the sum of three periods and I have tried to express this in the following equation;
The average of yesterday's H/L/C times 2 minus yesterdays low, represented below;
[[[[Yesterday's High + Yesterday's Low + Yesterday's Close]/3]*2] - Yesterday's Low]
but that is not the end, I also want to add the average of two days ago H/L/C times 2 minus 2 days ago low, represented below;
+ [[[[2 days ago High + 2 days ago Low + 2 days ago close]/3]*2] – 2 days ago Low]
Finally, I want to add a third days average of three days ago H/L/C times 2 minus 3 days ago low, represented below;
+ [[[[3 days ago High + 3 days ago Low + 3 days ago close]/3]*2] - 3 days ago Low]/3]
I want cross above level to be represented by the equation output of the three days, not just the first day. That is why I have tried to group them in this manner.
Thanks,
Russ
0
Comments
What is it?
It looks like it should pass syntax. Does it? If not, it may be more than the parser can handle in one line (in other words, nested too deep).
It might help to run each equation individually - i.e. close x day 1's equation, then close x day 2's equation, etc.
If that works, try combining 2 days - close x day 1 + day 2; and then close x day 1 + day 2 + day 3, then finally divide the sum of the 3 days by 3.
If the individual equations work, but it fails at some point when combining them, then it's likely to much for the scanner.
Another possibility is the scanner can handle it but the server is killing it for running too long. Try it against just the dow 30 or sp100.
[close x [ [statement 1] + [ statement 2] ] ]
Then, if that works, try putting a bracket after the "x" and before the first bracket of the first statement, and one more bracket just before the "/3]. It may not understand that you want to divide the sum of all three statements by 3.
[close x [ [statement 1] + [ statement 2] + [statement 3] ] /3 ]
Sounds counter intuitive - but if support says its not nested too deep, that might be it.
[[a + b + c+] /3] * 2]
[ [a + b + c +] * .67]