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## Comments

But, a half per cent of the open would be just a small fraction of the open. So, suppose the open is 100.

100 * .005 would be .5

So, your statement would be close > .5, which is bound to be true.

What you want is

and [close > open + [open*.005]]

So if open is 100, it would be "close > 100 + (100*.005)", same as "close > 100 + .5", same as "close > 100.5".

and [close > open*1.005]

... a little easier to write - just make sure you use 2 zeroes and not one zero by mistake.