Contraction of 55% between today's range and average range of 21-days

Teknical

Hello , Wishing you all a very Happy and prosperous 2025 .. Need a scan for today's range has been contracted more than equal to average range of 21-days / 21-bars
Today's Range Equation is : : high - low / close *100 and Average range for 21-days is: ( sma, ( high - low / close *100) 21).

markd

I think you could do it this way:

and [range < sma(21, range)]

I don't think it makes a difference to normalize the range by dividing by 100. Also, functions like sma( ) don't do calculations inside the brackets - you have to use a built-in term like range.

Looking at this again, I may have misunderstood what you want.

If want range less than 55% of the 21 day range:

and [range < sma(21,range) * .55]

Teknical

Thank you markd